Guesthouse Promenade
Osipovica 15, Medulin, Croatia
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Guesthouse Promenade
The 3-star Guesthouse Promenade Medulin sits 550 m from Medulin Sand Beach and offers a shared lounge and a restaurant. Featuring 10 rooms with views of the garden, the guest house is 3.5 km from the private Island Ceja.
Bijeca Beach is located merely 6 minutes' walk away, while the Levan is about 10 minutes' drive from this Medulin hotel. The Guesthouse Promenade Medulin places you 550 metres from Camping Medulin Beach. Guests can make memories with their children by visiting the Medulin Adrenalin Park, which is 2.5 km away. Pula airport is 5 km from this accommodation.
The rooms comprise a balcony and a living room complete with an air conditioner, as well as a multi-channel TV.
Guests will enjoy a games room arranged at the Guesthouse Promenade.
Vagabundo serves Croatian cuisine and is located right near the hotel.
Amenities
Main Features
- Free Wi-Fi
- Private beach
- On-site Dining
- Smoking
- Air conditioning
- No pets allowed
Facilities
- Smoking allowed in designated areas
- Free Wi-Fi in public areas
- Free parking
- Off-site car park
- No pets allowed
- Luggage storage
- Currency exchange
- ATM/Cash machine
- Coffee shop
- Electric kettle
- Cookware/ Kitchen utensils
- Restaurant
- Bar/ Lounge area
- Beach access
- Garden area
- Shops/Commercial services
- Air conditioning
- Heating
- Sitting area
- Dining table
- Flat-screen TV
- Parquet floor
Policy
Map
Local Attractions
Attractions
- Park suma Kasteja (900 m)
- Rudist (3 km)
- Bett (2.8 km)
- Sv. Foska (3.1 km)
- Metta Float Yoga & SUP (500 m)
- Residence Kamenjak Premantura (2.9 km)
- Sv Flor (3.3 km)
- Adrenalin Park Medulin (2.5 km)
- Medulin Village (450 m)
- 42cm Haubitzbatterie (2.8 km)
Airports
- Pula (14 km)
